Question
The distance between two successful crestof a water wave travelling at 3.6 m/s is 0.45m. Cal culate the frequency of the wave
Answers
Henry
P = (0.45m/3.6m) * 1s. = 0.125 s. = The
period of the wave.
Freq. = 1/P = 1/0.125 = 8 Cycles/s = 8
Hz.
period of the wave.
Freq. = 1/P = 1/0.125 = 8 Cycles/s = 8
Hz.
vetoboy
Wave speed = frequency*wavelength
v =f* λ
3.6 m/s =f*0.45 m.
f= (3.6 m/s)/(0.45 m)
= 8 hertz
v =f* λ
3.6 m/s =f*0.45 m.
f= (3.6 m/s)/(0.45 m)
= 8 hertz