Asked by Jake Monroe
the walls, floor, and ceiling of a room form a rectangular solid. The total surface are of the room is 992 square feet. The dimensions of the floor are 12 feet by 20 feet
a. What is the lateral area of the room
b. What is the height of the room.
a. What is the lateral area of the room
b. What is the height of the room.
Answers
Answered by
Henry
As = 2*(W*h)) + 2*(L*h) + 2(L*W)
a. As = Al + 2*(L*W) = 992 Ft^2
Al + 2*(20*12) = 992
Al = 992 - 480 = 512 Ft^2.=Lateral area.
b. Al = 2(W*h) + 2(L*h) = 512 Ft^2
2(12*h) + 2(20*h) = 512
Solve for h.
a. As = Al + 2*(L*W) = 992 Ft^2
Al + 2*(20*12) = 992
Al = 992 - 480 = 512 Ft^2.=Lateral area.
b. Al = 2(W*h) + 2(L*h) = 512 Ft^2
2(12*h) + 2(20*h) = 512
Solve for h.
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