There are
20 yellow
x green
80-x pink
Total 100
P(YP)=(20/100)(80-x)/99
P(GY)=(x/100)(20/99)
If P(YP)=P(GY) then
20(80-x)=20x after cancelling identical denominators
Solve for x:
x=1600/40=40
So there are 40 green and 40 pink mints.
If P(YP)>P(GY) then
20(80-x)>20x
40x<1600
x<40, or pink=(80-x)>40
A bag holds 20 yellow mints and 80 other green or pink mints. You choose a mint at random, eat it, and choose another.
a. Find the number of pink mints if P(yellow then pink) = P(green then yellow).
b. What is the least number of pink mints if P(yellow then pink) > P(green then yellow)?
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