Asked by Josh
Write out the form of the partial fraction decomposition of the function appearing in the integral:
integral (6x-58)/(x^2+2x-63)
Determine the numerical values of the coefficients, A and B, where A <= B
A=?
B=?
Thank you guys so much!
=)
integral (6x-58)/(x^2+2x-63)
Determine the numerical values of the coefficients, A and B, where A <= B
A=?
B=?
Thank you guys so much!
=)
Answers
Answered by
Reiny
I will split it up for you ...
(6x-58)/( (x+9)(x-7) )
let
A/(x+9) + B/(x-7) = (6x-58)/( (x+9)(x-7) )
A(x-7) + B(x+9) = 6x - 58
let x = 7
0 + 16B = -16
B = -1
let x = -9
-16A + 0 = -112
A = -7
so ....
(6x-58)/( (x+9)(x-7) ) = -7/(x+9) - 1/(x-7)
now it integrates easily using ln
take it from here
(6x-58)/( (x+9)(x-7) )
let
A/(x+9) + B/(x-7) = (6x-58)/( (x+9)(x-7) )
A(x-7) + B(x+9) = 6x - 58
let x = 7
0 + 16B = -16
B = -1
let x = -9
-16A + 0 = -112
A = -7
so ....
(6x-58)/( (x+9)(x-7) ) = -7/(x+9) - 1/(x-7)
now it integrates easily using ln
take it from here
Answered by
Josh
Thanks! Got it!
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