Question

1) Given the arithmetic sequence an = 4 - 3(n - 1), what is the domain for n?

All integers where n ≥ 1

All integers where n > 1

All integers where n ≤ 4

All integers where n ≥ 4

2) What is the 6th term of the geometric sequence where a1 = 1,024 and a4 = -16?

1

-0.25

-1

0.25

Answer 1

since the terms are number an, then n is any integer from one onward. n>=1.

since a4 = a1*r^3,
1024r^3 = -16
r^3 = -16/1024 = -2^4/2^10 = -2^-6
So, r = -2^-2 = -1/4

a6 = a4*r^2 = -16 * 1/16 = -1

Answer 2

Hhb