Asked by rohit singh
x=tcost & y=t+sint then find dx2/d2y
Answers
Answered by
drwls
The symbol
dx2/d2y
doesn't make sense.
Do you want d/dy (dx/dy) = d^2x/dy^2 ?
You can get dx/dy parametrically in terms of t using
dx/dy = (dx/dt)/(dy/dt)
After that, you can use the chain rule for d^2/dy^2. It will still be in terms of t.
dx2/d2y
doesn't make sense.
Do you want d/dy (dx/dy) = d^2x/dy^2 ?
You can get dx/dy parametrically in terms of t using
dx/dy = (dx/dt)/(dy/dt)
After that, you can use the chain rule for d^2/dy^2. It will still be in terms of t.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.