Asked by rohit singh
                x=tcost & y=t+sint    then find  dx2/d2y
            
            
        Answers
                    Answered by
            drwls
            
    The symbol 
dx2/d2y
doesn't make sense.
Do you want d/dy (dx/dy) = d^2x/dy^2 ?
You can get dx/dy parametrically in terms of t using
dx/dy = (dx/dt)/(dy/dt)
After that, you can use the chain rule for d^2/dy^2. It will still be in terms of t.
    
dx2/d2y
doesn't make sense.
Do you want d/dy (dx/dy) = d^2x/dy^2 ?
You can get dx/dy parametrically in terms of t using
dx/dy = (dx/dt)/(dy/dt)
After that, you can use the chain rule for d^2/dy^2. It will still be in terms of t.
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