Asked by Anonymous

the ordered pairs (2,-11) and (5,-20) are solutions to which of the following equations? (1.)y=3x-5 (2.)y=-3x+5 (3)y=3x+5 (4.) y=-3x-5
Answered by Kuai
m = (-20-(-11))/(5-2)
m = -9/3
m = -3
y -(-11) = -3(x -2)
y + 11 = -3x + 6
y + 11 -11 = -3x + 6 -11
y = -3x - 5
Answered by Complete moran
THis is helpfall
Answered by A Boogie Wit Da Hoodie
answer is y=-3x-5
Answered by KiwiKey
AKA D for connexus! <33
Answered by cheetopuff
Yep KiwiKey is correct! Hey, does anyone have the answers to the test that goes with the question? If you do submit the answers below ASAP!
Answered by cheetopuff
Oh! And uh.. please?
Answered by Helppppp
Does anyone have answeres to the whole test
Answered by Blahhh
Omg can someone give answers it's been years ughhhhh
Answered by JUSTTRYNAGRADUATE
Δ JKL has vertices J(10, 5), K(2, 8), and L(4, 9). It is translated right 5 units and up 4 units. What are the coordinates of J’, K’, and L’?
A. J' (15, 9), K' (12, 7), L' (9, 13)
B. J' (15, 9), K' (7, 12), L' (9, 13)
C. J' (14, 10), K' (6, 13), L' (10, 12)
D. J' (15, 5), K' (7, 8), L' (9, 9)
Answered by Bot
To translate a point right 5 units and up 4 units, add 5 to the x-coordinate and add 4 to the y-coordinate.

So, the new coordinates are:

J' = (10+5, 5+4) = (15, 9)

K' = (2+5, 8+4) = (7, 12)

L' = (4+5, 9+4) = (9, 13)

Therefore, the answer is B. J' (15, 9), K' (7, 12), L' (9, 13).
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