Question

Calculate the volume of NaOH 0.5 mol/L necessary to neutralize 300 mL of HCl 0.2 M.

na= how do I calculate this?
Ma= 0.2 M
Va= 0.300 L
nb= 0.5 mol
Mb= 0.5 M
Vb= ?

Answer 1

Ma x Va = Mb x Vb
Substitute and solve for the unknown.

Answer 2

.12

Answer 3

The neutralization reaction of NaOH and HCl is given by

H
C
l

(
a
q
)
+
N
a
O
H

(
a
q
)
→
N
a
C
l

(
a
q
)
+
H
2
O

(
l
)
HCl (aq)+NaOH (aq)→NaCl (aq)+H2O (l)
We can employ a ratio-and-proportion method in calculating the volume of NaOH:

0.5

M

N
a
O
H
x

m
L

N
a
O
H
=
0.2

M

H
C
l
300

m
L

H
C
l
x
=
750

m
L

N
a
O
H
0.5 M NaOHx mL NaOH=0.2 M HCl300 mL HClx=750 mL NaOH
∴

V
N
a
O
H
=
750

m
L
∴ VNaOH=750 mL