Asked by Ara
2. A rectangle whose perimeter is 80 m has an area of 384 m^2. Find the dimensions of the rectangle. Solve it as a polynomial.
Answers
Answered by
Steve
If the width is w, we have
w(40-w) = 384
w^2 - 40w + 384 = 0
since 384 = 4*96 or 8*48 or 12*32 or 16*24 - aha!
(w-16)(w-24) = 0
Now you can easily figure the dimensions. Note that width is usually considered to be less than the length.
w(40-w) = 384
w^2 - 40w + 384 = 0
since 384 = 4*96 or 8*48 or 12*32 or 16*24 - aha!
(w-16)(w-24) = 0
Now you can easily figure the dimensions. Note that width is usually considered to be less than the length.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.