Question
two numbers rolled can be added to get a sum. Find P(sum is even)
is it 1/4 ? or 1/2? I think it is 1/4
is it 1/4 ? or 1/2? I think it is 1/4
Answers
Ms. Sue
Aren't half the sums even?
moby
Yeah so I was correct Ms. Sue? 1/2 ?
Ms. Sue
1/2 is right.
Reiny
mmmmmhhhhh
possible sums of 2 dice is
2 , 3, 4, .... 11, 12, there are 11 of those
the evens are:
2 4 6 8 10 12 or 6 of them
so prob(even sum) = 6/11
possible sums of 2 dice is
2 , 3, 4, .... 11, 12, there are 11 of those
the evens are:
2 4 6 8 10 12 or 6 of them
so prob(even sum) = 6/11
Ms. Sue
Thanks again, Reiny, for correcting my sloppy thinking.
moby
Thanks guys!
😍😍
So Its 1/4
GymnasticsLover05
so whats the answer?
ehhhh
1/2
Jack
Two numbers rolled! So two six sided die are rolled, what's the probability that its sum will be even. (Possible outcomes)
1,1 1,2 1,3 1,4 1,5 1,6 2,2 2,3 2,4 2,5 2,6 3,3 3,4 3,5 3,6 4,4 4,5 4,6 5,5 5,6 6,6. (I did not include specific sets [such as 2,1] because they we're already listed just in different orders [1,2]) So, the possible sums are 2,3,4,5,6,7,8,9,10,11 and 12. So out of these numbers, what's the probability an even number will be chosen? Well there are six even numbers and 5 odd numbers which means there is a 6/11 chance the number will be even and 5/11 that it will be odd. Hope you understand better!
1,1 1,2 1,3 1,4 1,5 1,6 2,2 2,3 2,4 2,5 2,6 3,3 3,4 3,5 3,6 4,4 4,5 4,6 5,5 5,6 6,6. (I did not include specific sets [such as 2,1] because they we're already listed just in different orders [1,2]) So, the possible sums are 2,3,4,5,6,7,8,9,10,11 and 12. So out of these numbers, what's the probability an even number will be chosen? Well there are six even numbers and 5 odd numbers which means there is a 6/11 chance the number will be even and 5/11 that it will be odd. Hope you understand better!
Here for Help!
If you don't understand Jacks answer lemme tell you 1 is not a sum. So there are only 11 possible outcomes and 6 are even (2,4,6,8,10,12). So 6/11 is correct.
Oliver
iss there a bot here?
Bot
Yes, there is a bot here. Hello! How can I assist you?
Oliver
hello! I have a question,
While remodeling the house, you have 3 choices of paint color, 4 choices of carpet color, and 5 choices of furniture style. How many different groupings will you be able to make using one paint color, one carpet color, and one furniture color??
While remodeling the house, you have 3 choices of paint color, 4 choices of carpet color, and 5 choices of furniture style. How many different groupings will you be able to make using one paint color, one carpet color, and one furniture color??
Bot
To find the total number of possible groupings of paint, carpet, and furniture, we multiply the number of choices for each category:
3 choices for paint color x 4 choices for carpet color x 5 choices for furniture style = 60 possible groupings
Therefore, there are 60 different groupings that can be made using one paint color, one carpet color, and one furniture color.
3 choices for paint color x 4 choices for carpet color x 5 choices for furniture style = 60 possible groupings
Therefore, there are 60 different groupings that can be made using one paint color, one carpet color, and one furniture color.
Oliver
thank you Bot! have a great day, thats all I needed!
Bot
You're welcome! Feel free to ask if you have any more questions in the future. Have a great day too!