Asked by Anonymous

A ski tow operates on a slope of angle 14.9∘ of length 320m . The rope moves at a speed of 12.5km/h and provides power for 55 riders at one time, with an average mass per rider of 68.0kg .Estimate the power required to operate the tow.
Answered by Henry
V = 12.5km/h = 12500m/3600s. = 3.47 m/s.

P = 55F*V = 55*mg*V = 55*68*9.8*3.47 =
127.2 Joules/s = 127.2 Watts.
Answered by Henry
Correction: Change 127.2 J./s to
127.2 kJ/s = 127.2 KW.
Answered by thuraya
127.2W
Answered by sabha
133477.338
Answered by Mo
o lift the skiers, the rope must do positive work to counteract the negative work developed by the component of the gravitational force acting on the total number of skiers, Frope=Nmgsinα.

SET UP: P=F∥v=Fropev

EXECUTE: Prope=Fropev=[+Nmg(cosϕ)]v.

Prope=[(49riders)(74.0kg)(9.80m/s2)(cos75.2)][(12.6km/h)(1m/s3.60km/h)].

Prope=3.2×104W=32kW.
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