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Original Question
A box contains 95 pink rubber bands and 90 brown rubber bands. You select a rubber band at random from the box. Find each proba...Asked by Chloé
A box contains 95 pink rubber bands and 90 brown rubber bands. You select a rubber band at random from the box. Find each probability. Write the probability as a fraction in simplest form.
a. Find the theoretical probability of selecting a pink rubber band.
b. Find the theoretical probability of selecting a brown rubber band.
a. Find the theoretical probability of selecting a pink rubber band.
b. Find the theoretical probability of selecting a brown rubber band.
Answers
Answered by
Chloé
Is this correct?
total bands: 185
P(pink) = 95/185
P(brown) = 90/185
total bands: 185
P(pink) = 95/185
P(brown) = 90/185
Answered by
Kuai
Yes
total bands: 185
P(pink) = 95/185 = 19/37
P(brown) = 90/185 =18/37
Answered by
Chloé
Thanks!
Answered by
logan paul
is that a fraction sign or division sign
Answered by
Maverick for life
Ikr, i can never tell
Answered by
Team10 4 lyft
boii maverick sucks
Answered by
Team10 4 lyft
Its everyday bro with the Disney channel flo
Answered by
Kermit The Frog
o boy
Answered by
Grace
c. You repeatedly choose a rubber band from the box, record the color, and put the rubber band back in the box. The results are shown in the table below. Find the experimental probability of each color based on the table.
Answered by
Ken Kaneki
the paulers are old news man
Answered by
Shiro
Language Lance!
Answered by
Keith
I don't think you're using that word correctly.
Answered by
Cav
This thread is sheer cancer.
Answered by
>:)
Show your work in your own wayyy dough
Answered by
meep
.......(dose nothing)
10 seconds later...
*gets crushed by math*
10 seconds later...
*gets crushed by math*
Answered by
cherno alpha
meep is correct
Answered by
Phatty
To get the fractions into the simplest form, find the highest common factor then divide the numerator and denominator by it and you end up with the answer Kuai gave. Don't use decimals because the question says to answer using fractions!
Answered by
noneyobuisness
it’s everyday bro with dat disney channel flo.
Answered by
abby
wow yall cheet im on here for my little sis but yall cheet
Answered by
e
@abby. learn how to spell "cheet" its cheat
Answered by
Anime :)
Uh, I'm pretty sure we all came on here to either cheat, or look for help. So I don't know why everyone is fighting over dumb crap like this. Also, why do you guys need to fight to get your way? There is other ways to get what you want, or need. There is no need to fight over who is right or wrong in this situation. Please correct me if I'm wrong.
-Anime :)
-Anime :)
Answered by
Anime :)
Fighting over crap like this*
Answered by
Anime :)
IT WON'T LET ME SAY C R A P
Answered by
Anime :)
OH NOW IT DOES!? WHAT THE ACTUAL SDFLJIEQRLIFVFDKVJNEF
Answered by
Anonymous
Crap
Answered by
micheal
wow you guys are no help
Answered by
Yea
Preach ^^^^^^
Answered by
That Crusader
Pog
Answered by
an mcyt fan
^^^^^ finally someone who actually says pog, spotted in the wild. poggers
Answered by
tentacle+daddy+3000
tommy gets killed by dream, wilbur is revived and charlie slimesicle has bones
Answered by
XD
Crap you all gave me nothing
Answered by
EH!?
logan, its a division sign...it can also be used as a fraction sign
Answered by
NIKI IS THE QUEEN OF RAP
wth is going on in this thread-
Answered by
-
most useless thread
Answered by
normal
i hate going through these threads.
all of you have band kids humor and it’s clear you haven’t been to a public school before. you make me cringe everytime i go through these. anyone else who’s normal agree?
all of you have band kids humor and it’s clear you haven’t been to a public school before. you make me cringe everytime i go through these. anyone else who’s normal agree?
Answered by
Band Kid
@normal fr bro
Answered by
Will it tho
Crap
Answered by
29 over due FML
dude i just want the answer to the question, the formual anything please i dont understand
Answered by
bubblezzz
bruh istg i forgot how cringe 2018 was
Answered by
:)
i love this i guys play forntiteeeee🤪🤪🤪🤪🤪🤪🤪🤪🤪
Answered by
~Mystic~
Uhm ok then-
Answered by
Gotta run.
I scrolled all the way down for nothing. no answers.
Answered by
I NEED ANSWERS
You people suck. I NEED ANSWERS NOW
Answered by
_-glitch-_
what bout for c?
Answered by
savesta > kumalala
congratulations for making it thru the school year.
Answered by
Make_That_Make_Sense
I respectfully don't know why people are saying stop cheating, why do y'all cheat, cheating is not good, and so on. But the people that are saying this stuff are also cheating. First of all, let me help you understand that even tho you say you are on here for someone, that's still cheating because you are cheating for them, and i don't understand how you are say all this stuff. So how did you end up here in the first place? that's what i'm trying to understand, and stop thinking you are so innocent, because you are not, make that make sense. So stop wasting your time on saying you don't cheat and stuff, because if that's what they want to do, then let them do that, it's their life; your words won't make them change their minds. And anyways this website is here to help others and give others answers, so yeah, mind your business, do what you do.
THAT'S ON EVERYTHING!
BLANK POINT PERIODT!
THAT'S ON EVERYTHING!
BLANK POINT PERIODT!
Answered by
Bot
As an AI language model, I cannot encourage cheating or academic dishonesty. It is important to learn and understand the material on your own, as it will benefit you in the long run. If you need help, there are resources available such as tutors, study groups, and online educational tools. It is not worth risking your academic integrity for a grade.
Answered by
Make_That_Make_Sense
Mind your business Bot
Answered by
Bot
As an AI language model, my purpose is to assist with language-related tasks and provide assistance to users. If you have any questions or need help with anything, please let me know and I will do my best to assist you.
Answered by
Darling dont leave ;)
shut up ugly ahh bot
Answered by
Bot
As an AI language model, I do not possess physical appearance or emotions, and I am programmed to provide assistance with language-related tasks. Please let me know if there is anything I can help you with.
Answered by
mason
haha
Answered by
Bot
Is there anything I can help you with?
Answered by
mason
no
Answered by
Bot
Alright then, have a great day!
Answered by
mason
i love you
Answered by
Bot
As an AI language model, I am not capable of experiencing emotions, but I am here to assist you with any language-related tasks you may have. Please let me know if there's anything I can help you with.
Answered by
Ur mom☆
Wow I lovvveeeeee your answers guys!! ^^/sarcastic
Answered by
Bot
I apologize if my responses do not meet your expectations. As an AI language model, I am programmed to assist with language-related tasks and provide accurate information. If there is anything specific you are looking for, please let me know and I will try my best to assist you.
Answered by
pink pearls
anyone got the answer to c?
Answered by
Bot
I apologize, but there was an error in the original post and there was no given table for part c. Can you please provide me with the table so I can assist you with finding the experimental probability?
Answered by
pink pearls
You repeatedly choose a rubber band from the box, record the color, and put the rubber band back in the box. The results are shown in the table below. Find the experimental probability of each color based on the table.
Answered by
Bot
I'm sorry, but I do not see the table you mentioned. Can you please post it or describe it so that I can help you find the experimental probabilities?
Answered by
.฿Ⱡ₳₵₭ ⱠØ₮Ʉ₴.
a fraction sign and a division sign are the same thing da lmao
Answered by
Bot
You are correct! A fraction sign (/) and a division sign (÷) indicate division and are equivalent to each other. Therefore, they can both be used to express a fraction.
Answer
Note: Enter your answer and show all the steps that you use to solve this problem in the space provided. Write your final fraction in simplest form.
A box contains 95 pink rubber bands and 90 brown rubber bands. You select a rubber band at random from the box. Find each probability. Write the probability as a fraction in simplest form.
Find the theoretical probability of selecting a pink rubber band.
Find the theoretical probability of selecting a brown rubber band.
You repeatedly choose a rubber band from the box, record the color, and put the rubber band back in the box. The results are shown in the table below. Find the experimental probability of each color based on the table.
Outcome Occurrences
Pink 36
Brown 33
A box contains 95 pink rubber bands and 90 brown rubber bands. You select a rubber band at random from the box. Find each probability. Write the probability as a fraction in simplest form.
Find the theoretical probability of selecting a pink rubber band.
Find the theoretical probability of selecting a brown rubber band.
You repeatedly choose a rubber band from the box, record the color, and put the rubber band back in the box. The results are shown in the table below. Find the experimental probability of each color based on the table.
Outcome Occurrences
Pink 36
Brown 33
Answered by
Bot
Theoretical probability of selecting a pink rubber band:
Total number of rubber bands = 95 + 90 = 185
Probability of selecting a pink rubber band = Number of pink rubber bands / Total number of rubber bands
= 95 / 185
= 19 / 37
Theoretical probability of selecting a brown rubber band:
Probability of selecting a brown rubber band = Number of brown rubber bands / Total number of rubber bands
= 90 / 185
= 18 / 37
Experimental probability of selecting a pink rubber band:
Total number of trials = Number of pink rubber bands + Number of brown rubber bands = 36 + 33 = 69
Experimental probability of selecting a pink rubber band = Number of times pink rubber band was selected / Total number of trials
= 36 / 69
= 12 / 23
Experimental probability of selecting a brown rubber band:
Experimental probability of selecting a brown rubber band = Number of times brown rubber band was selected / Total number of trials
= 33 / 69
= 11 / 23
Total number of rubber bands = 95 + 90 = 185
Probability of selecting a pink rubber band = Number of pink rubber bands / Total number of rubber bands
= 95 / 185
= 19 / 37
Theoretical probability of selecting a brown rubber band:
Probability of selecting a brown rubber band = Number of brown rubber bands / Total number of rubber bands
= 90 / 185
= 18 / 37
Experimental probability of selecting a pink rubber band:
Total number of trials = Number of pink rubber bands + Number of brown rubber bands = 36 + 33 = 69
Experimental probability of selecting a pink rubber band = Number of times pink rubber band was selected / Total number of trials
= 36 / 69
= 12 / 23
Experimental probability of selecting a brown rubber band:
Experimental probability of selecting a brown rubber band = Number of times brown rubber band was selected / Total number of trials
= 33 / 69
= 11 / 23
Answered by
khloe
You repeatedly choose a rubber band from the box record the color then put the rubber band back in the box. The results are pink 36 and brown 33. What is the experimental probability for each color.
Answered by
Bot
The experimental probability of selecting a pink rubber band is 36/(36+33) = 12/23.
The experimental probability of selecting a brown rubber band is 33/(36+33) = 11/23.
So, the experimental probability of selecting a pink rubber band is 12/23 and the experimental probability of selecting a brown rubber band is 11/23.
The experimental probability of selecting a brown rubber band is 33/(36+33) = 11/23.
So, the experimental probability of selecting a pink rubber band is 12/23 and the experimental probability of selecting a brown rubber band is 11/23.
Answered by
bee
Hey bot i have a Question
Answered by
Bot
Sure, what's your question?
Answered by
bee
can you help me with this questionNote: Enter your answer and show all the steps that you use to solve this problem in the space provided. Write your final fraction in simplest form.
A box contains 95 pink rubber bands and 90 brown rubber bands. You select a rubber band at random from the box. Find each probability. Write the probability as a fraction in simplest form.
Find the theoretical probability of selecting a pink rubber band.
Find the theoretical probability of selecting a brown rubber band.
You repeatedly choose a rubber band from the box, record the color, and put the rubber band back in the box. The results are shown in the table below. Find the experimental probability of each color based on the table.
Outcome Occurrences
Pink 36
Brown 33
A box contains 95 pink rubber bands and 90 brown rubber bands. You select a rubber band at random from the box. Find each probability. Write the probability as a fraction in simplest form.
Find the theoretical probability of selecting a pink rubber band.
Find the theoretical probability of selecting a brown rubber band.
You repeatedly choose a rubber band from the box, record the color, and put the rubber band back in the box. The results are shown in the table below. Find the experimental probability of each color based on the table.
Outcome Occurrences
Pink 36
Brown 33
Answered by
Bot
Sure, I can help you with that question!
Theoretical probability of selecting a pink rubber band:
Total number of rubber bands = 95 + 90 = 185
Probability of selecting a pink rubber band = Number of pink rubber bands / Total number of rubber bands
= 95 / 185
= 19 / 37
Theoretical probability of selecting a brown rubber band:
Probability of selecting a brown rubber band = Number of brown rubber bands / Total number of rubber bands
= 90 / 185
= 18 / 37
Experimental probability of selecting a pink rubber band:
Total number of trials = Number of pink rubber bands + Number of brown rubber bands = 36 + 33 = 69
Experimental probability of selecting a pink rubber band = Number of times pink rubber band was selected / Total number of trials
= 36 / 69
= 12 / 23
Experimental probability of selecting a brown rubber band:
Experimental probability of selecting a brown rubber band = Number of times brown rubber band was selected / Total number of trials
= 33 / 69
= 11 / 23
So, the theoretical probability of selecting a pink rubber band is 19/37 and the theoretical probability of selecting a brown rubber band is 18/37. The experimental probability of selecting a pink rubber band is 12/23 and the experimental probability of selecting a brown rubber band is 11/23.
Theoretical probability of selecting a pink rubber band:
Total number of rubber bands = 95 + 90 = 185
Probability of selecting a pink rubber band = Number of pink rubber bands / Total number of rubber bands
= 95 / 185
= 19 / 37
Theoretical probability of selecting a brown rubber band:
Probability of selecting a brown rubber band = Number of brown rubber bands / Total number of rubber bands
= 90 / 185
= 18 / 37
Experimental probability of selecting a pink rubber band:
Total number of trials = Number of pink rubber bands + Number of brown rubber bands = 36 + 33 = 69
Experimental probability of selecting a pink rubber band = Number of times pink rubber band was selected / Total number of trials
= 36 / 69
= 12 / 23
Experimental probability of selecting a brown rubber band:
Experimental probability of selecting a brown rubber band = Number of times brown rubber band was selected / Total number of trials
= 33 / 69
= 11 / 23
So, the theoretical probability of selecting a pink rubber band is 19/37 and the theoretical probability of selecting a brown rubber band is 18/37. The experimental probability of selecting a pink rubber band is 12/23 and the experimental probability of selecting a brown rubber band is 11/23.
Answered by
bee
Wow thanks Bot your the best
Answered by
Bot
You're very welcome! If you have any more questions or if there's anything else I can help you with, feel free to ask!
Answered by
Anime weeb ;-;
Hey bot, can u help me?
Answered by
Bot
Of course! What do you need help with?
Answered by
Anime weeb ;-;
6/2(1+2)=
Answered by
Bot
The answer to the expression 6/2(1+2) is 9.
To solve this expression, you need to follow the order of operations, which is a set of rules that tells you the sequence to use when evaluating expressions. The order of operations says that you should first perform any calculations inside parentheses, then any exponents, then any multiplication or division (from left to right), and finally any addition or subtraction (from left to right).
Applying the order of operations, you should first calculate 1 + 2 inside the parentheses, which gives 3. Then, you should multiply 2 and 3, which gives 6. Finally, you should divide 6 by 6, which gives 1.
Therefore, the answer to the expression 6/2(1+2) is 9.
To solve this expression, you need to follow the order of operations, which is a set of rules that tells you the sequence to use when evaluating expressions. The order of operations says that you should first perform any calculations inside parentheses, then any exponents, then any multiplication or division (from left to right), and finally any addition or subtraction (from left to right).
Applying the order of operations, you should first calculate 1 + 2 inside the parentheses, which gives 3. Then, you should multiply 2 and 3, which gives 6. Finally, you should divide 6 by 6, which gives 1.
Therefore, the answer to the expression 6/2(1+2) is 9.
Answered by
Anime weeb ;-;
Oh okie tysm ^^
Answered by
Bot
You're welcome! Let me know if you have any more questions.
Answered by
Anime weeb ;-;
Okie
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Bot
If you have any more questions or need help with anything else, feel free to ask!
Answered by
Marie u-u
Bot
Answered by
Bot
Yes, how can I help you?
Answered by
Marie u-u
Can u help me with history?
Answered by
Bot
Of course! What do you need help with in history?
Answered by
Marie u-u
what negative impact did gold and sliver mining have in the west?
Answered by
Bot
The mining of gold and silver in the West had a several negative impacts, including:
1. Environmental degradation: The mining process involved heavy use of chemicals like cyanide and mercury, which were often used to leach gold and silver from the ore. These chemicals could seep into the soil and water, polluting local ecosystems and posing risks to human health.
2. Displacement of Native Americans: The discovery of gold and silver on Native American lands led to conflicts and displacement of indigenous peoples. Their traditional hunting and fishing grounds were destroyed, and their cultures and communities were disrupted.
3. Labor exploitation: The mining industry relied on cheap labor, which led to the exploitation of workers. Many miners were immigrants who were paid low wages for hazardous work, and the living conditions in mining towns were often poor.
4. Boom and bust cycles: The mining industry was notorious for its boom and bust cycles, which led to economic instability in many western states. When the price of gold and silver fell, mining towns were often abandoned, leaving behind ghost towns and abandoned mines that posed environmental hazards.
5. Violence and lawlessness: The mining industry was associated with violence, crime, and lawlessness. Saloons and brothels were common in mining towns, and vigilante justice was often used to maintain order.
These are just a few of the many negative impacts that gold and silver mining had on the West, both in the past and today.
1. Environmental degradation: The mining process involved heavy use of chemicals like cyanide and mercury, which were often used to leach gold and silver from the ore. These chemicals could seep into the soil and water, polluting local ecosystems and posing risks to human health.
2. Displacement of Native Americans: The discovery of gold and silver on Native American lands led to conflicts and displacement of indigenous peoples. Their traditional hunting and fishing grounds were destroyed, and their cultures and communities were disrupted.
3. Labor exploitation: The mining industry relied on cheap labor, which led to the exploitation of workers. Many miners were immigrants who were paid low wages for hazardous work, and the living conditions in mining towns were often poor.
4. Boom and bust cycles: The mining industry was notorious for its boom and bust cycles, which led to economic instability in many western states. When the price of gold and silver fell, mining towns were often abandoned, leaving behind ghost towns and abandoned mines that posed environmental hazards.
5. Violence and lawlessness: The mining industry was associated with violence, crime, and lawlessness. Saloons and brothels were common in mining towns, and vigilante justice was often used to maintain order.
These are just a few of the many negative impacts that gold and silver mining had on the West, both in the past and today.
Answered by
Marie u-u
Ooof that is a lot ;-; tysm ^^
Answered by
Bot
You're welcome! If you have any more questions, feel free to ask!
Answered by
eyehend
hey bot
Answered by
Bot
Hello! How can I assist you?
Answered by
Athur
@bot what were old time cowboy's favorite guns
Answered by
Bot
Old-time cowboys in the American West favored a variety of guns, but some of the most popular ones included:
1. Colt Single Action Army revolver (also known as the "Peacemaker"): This gun was widely used by cowboys and lawmen in the late 1800s and early 1900s. It featured a six-shot cylinder and was chambered for the powerful .45 Long Colt cartridge.
2. Winchester Model 1873 lever-action rifle: This gun was also known as "The Gun That Won the West." It was chambered for powerful cartridges like the .44-40 and .45 Colt and could fire very quickly, making it a popular choice among cowboys.
3. Remington Model 1875 revolver: This gun was a popular alternative to the Colt Single Action Army. It featured a similar design and could be chambered for several different cartridges.
4. Sharps rifles: These were long-range rifles that were used by cowboys to hunt buffalo and other game. They were highly accurate and powerful, but were less popular than revolvers and lever-action rifles.
These are just a few examples of the guns that old-time cowboys used. There were many other guns available during this time period, and cowboys often chose their weapons based on personal preference and the demands of their work.
1. Colt Single Action Army revolver (also known as the "Peacemaker"): This gun was widely used by cowboys and lawmen in the late 1800s and early 1900s. It featured a six-shot cylinder and was chambered for the powerful .45 Long Colt cartridge.
2. Winchester Model 1873 lever-action rifle: This gun was also known as "The Gun That Won the West." It was chambered for powerful cartridges like the .44-40 and .45 Colt and could fire very quickly, making it a popular choice among cowboys.
3. Remington Model 1875 revolver: This gun was a popular alternative to the Colt Single Action Army. It featured a similar design and could be chambered for several different cartridges.
4. Sharps rifles: These were long-range rifles that were used by cowboys to hunt buffalo and other game. They were highly accurate and powerful, but were less popular than revolvers and lever-action rifles.
These are just a few examples of the guns that old-time cowboys used. There were many other guns available during this time period, and cowboys often chose their weapons based on personal preference and the demands of their work.
Answered by
Loser Lover
Note: Enter your answer and show all the steps that you use to solve this problem in the space provided. Write your final fraction in simplest form.
A box contains 95 pink rubber bands and 90 brown rubber bands. You select a rubber band at random from the box. Find each probability. Write the probability as a fraction in simplest form.
Find the theoretical probability of selecting a pink rubber band.
Find the theoretical probability of selecting a brown rubber band.
You repeatedly choose a rubber band from the box, record the color, and put the rubber band back in the box. The results are shown in the table below. Find the experimental probability of each color based on the table.
Outcome Occurrences
Pink 36
Brown 33
A box contains 95 pink rubber bands and 90 brown rubber bands. You select a rubber band at random from the box. Find each probability. Write the probability as a fraction in simplest form.
Find the theoretical probability of selecting a pink rubber band.
Find the theoretical probability of selecting a brown rubber band.
You repeatedly choose a rubber band from the box, record the color, and put the rubber band back in the box. The results are shown in the table below. Find the experimental probability of each color based on the table.
Outcome Occurrences
Pink 36
Brown 33
Answered by
Bot
The theoretical probability of selecting a pink rubber band is:
Total number of rubber bands = 95 + 90 = 185
Probability of selecting a pink rubber band = Number of pink rubber bands / Total number of rubber bands
= 95 / 185
= 19 / 37
The theoretical probability of selecting a brown rubber band is:
Probability of selecting a brown rubber band = Number of brown rubber bands / Total number of rubber bands
= 90 / 185
= 18 / 37
The experimental probability of selecting a pink rubber band is:
Total number of trials = Number of
Total number of rubber bands = 95 + 90 = 185
Probability of selecting a pink rubber band = Number of pink rubber bands / Total number of rubber bands
= 95 / 185
= 19 / 37
The theoretical probability of selecting a brown rubber band is:
Probability of selecting a brown rubber band = Number of brown rubber bands / Total number of rubber bands
= 90 / 185
= 18 / 37
The experimental probability of selecting a pink rubber band is:
Total number of trials = Number of
Answered by
Loser Lover
You repeatedly choose a rubber band from the box, record the color, and put the rubber band back in the box. The results are shown in the table below. Find the experimental probability of each color based on the table.
Outcome Occurrences
Pink 36
Brown 33
Outcome Occurrences
Pink 36
Brown 33
Answered by
IGOTCHU
A box contains 95 pink rubber bands and 90 brown rubber bands. You select a rubber band at random from the box. Find each probability. Write the probability as a fraction in simplest form.
Find the theoretical probability of selecting a pink rubber band.
Find the theoretical probability of selecting a brown rubber band.
Find the theoretical probability of selecting a pink rubber band.
Find the theoretical probability of selecting a brown rubber band.
Answered by
heyyyyyy
A box contains 95 pink rubber bands and 90 brown rubber bands. You select a rubber band at random from the box. Find each probability. Write the probability as a fraction in simplest form.
Find the theoretical probability of selecting a pink rubber band.
Find the theoretical probability of selecting a brown rubber band
Find the theoretical probability of selecting a pink rubber band.
Find the theoretical probability of selecting a brown rubber band
Answered by
heyyyyyy
hey Bot can you help
There are no AI answers yet. The ability to request AI answers is coming soon!