Question
Determine the mass of carbon monoxide that is produced when 45.6 g of methane CH4 react with 73.2 g of oxygen gas, O2. The products are CO and H2O. Please check my work:
CH4 + 3O2 ---> 2CO + 2H20
nCH4=2.84 mol nO2=4.58 mol
Limiting Reactant:
1 mol CH4/2.84 mol CH4 = 3 mol O2/X O2 mol
xO2=8.52 mol
nCO=8.52 mol
mCO=nXM
=238.65 grams
CH4 + 3O2 ---> 2CO + 2H20
nCH4=2.84 mol nO2=4.58 mol
Limiting Reactant:
1 mol CH4/2.84 mol CH4 = 3 mol O2/X O2 mol
xO2=8.52 mol
nCO=8.52 mol
mCO=nXM
=238.65 grams
Answers
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