Asked by TANYA

Evaluate!!!!


integral -10 to 10 ((2e^x)/(sinhx+coshx))dx

Thanks!
Answered by TANYA
I need someone to show me steps. I used wolframalpha and got 40 but don't know how to solve this

Thanks!!!
Answered by Steve
recall that
sinhx = (e^x-e^-x)/2
coshx = (e^x+e^-x)/2
so,
sinhx+coshx = e^x

2e^x/e^x = 2
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