Asked by Leah

Five cards are dealt from a shuffled deck of 52. Find the probability that:

a) The hand has 3 spades and 2 hearts.

b) The hand has 2 aces, 2 kings, and one other card.
Answered by Reiny
a) prob = C(13,3) * C(13,2)/C(52,5)
= 286*78/2598960
= 286/33320
= 11/99960

b) prob = C(4,2) * C(4,2)* C(44,1)/C(52,5)
= 6*6*44/2598960
= 3*11/54145
= 33/54145
Answered by Leah
is C for nCr???? i'm a little confused
Answered by Reiny
yes

C(n,r) = <sub>n</sub>C<sub>r</sub>

its an easier notation to type
Answered by Leah
Ohhhhhhh! okay, thank you! :)
Answered by Leah
Wait, how'd you get 33320 in A?
Answered by Steve
2598960/78 = 33320
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