Asked by help please
simplify 10p4
A. 210
B. 360
C. 5,040
D. 151,200
simplify 9c4
A. 126
B. 15,120
C. 5
D. 3,024
A. 210
B. 360
C. 5,040
D. 151,200
simplify 9c4
A. 126
B. 15,120
C. 5
D. 3,024
Answers
Answered by
Reiny
Use your definitions and evaluate
e.g.
<sub>11</sub>C<sub>5</sub> (not your question)
= 11! / (5!6!)
= 462
e.g.
<sub>11</sub>C<sub>5</sub> (not your question)
= 11! / (5!6!)
= 462
Answered by
Anonymous
I need answer
Answered by
Anonymous
The answer is 5,040
Answered by
dark dream
Test answers
1. D
2. D
3. C
4. A
5. A
6. C
7. D
8. A
9. D
10. B
11. C
12. B
13. C
14. A
15. C
16. B
for probability unit test part 1, i might post the part 2 answers
1. D
2. D
3. C
4. A
5. A
6. C
7. D
8. A
9. D
10. B
11. C
12. B
13. C
14. A
15. C
16. B
for probability unit test part 1, i might post the part 2 answers
Answered by
RosesAreRosie
@Reiny could you explain to me how to solve the equation? What does the "C" mean?
Answered by
Crazy
Are dark dreams answers correct or not?????
Answered by
meep
so is dark dreams right?
Answered by
Hawks/ Kegio
the answer to 10p4 is 5,040
Answered by
50%
Dark dream is not correct I only got 50%
Answer
Bot can you simplify 10p4
Answered by
cam
Bot can you please simplify 9c4
Answered by
cam
bot can you please . Simplify 10P4
.
.
Answered by
cam
bot please Simplify 8C5
Answered by
Your Name
bot what does the ! mean in 8!
Answered by
Your Name
thanks bot
Answered by
Your Name
bot, can you simplify 15C3?
Answered by
Your Name
bot…
You and 3 friends go to a concert. In how many different ways can you sit in the assigned seats?
You and 3 friends go to a concert. In how many different ways can you sit in the assigned seats?
Answered by
Your Name
bot, you own 6 pairs of jeans and want to take 2 of them with you on vacation. In how many ways can you choose 2 pairs of jeans?
Answered by
Help
Bot can you simplify 9c4-
Answered by
Random gurl
Hey bot I need helllppppp
Answered by
Random gurl
How many ways can 4 students be chosen from a class of 12 to represent their class at a banquet
Answered by
Random gurl
Can you help with this too?
you and 5 friends go to a concert. In how many different ways can you sit in the assigned seats?
you and 5 friends go to a concert. In how many different ways can you sit in the assigned seats?
Answered by
Random gurl
and this is the last one.
You own 5 pairs of jeans and want to take 2 of them with you on vacation. In how many ways can you choose 2 pairs to take with you
You own 5 pairs of jeans and want to take 2 of them with you on vacation. In how many ways can you choose 2 pairs to take with you
Answered by
Random gurl
okay! Thank you Bot!
Answered by
Bot
We know that:
10P4 = 10! / (10 - 4)!
= 10! / 6!
= (10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1) / (6 × 5 × 4 × 3 × 2 × 1)
= 10 × 9 × 8 × 7
= 5,040
Therefore, the answer is 5,040.
10P4 = 10! / (10 - 4)!
= 10! / 6!
= (10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1) / (6 × 5 × 4 × 3 × 2 × 1)
= 10 × 9 × 8 × 7
= 5,040
Therefore, the answer is 5,040.
Answered by
Bot
We know that:
9C4 = 9! / (4! × (9 - 4)!)
= 9! / (4! × 5!)
= (9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1) / [(4 × 3 × 2 × 1) × (5 × 4 × 3 × 2 × 1)]
= (9 × 2 × 3 × 7)
= 378
Therefore, the answer is 378.
9C4 = 9! / (4! × (9 - 4)!)
= 9! / (4! × 5!)
= (9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1) / [(4 × 3 × 2 × 1) × (5 × 4 × 3 × 2 × 1)]
= (9 × 2 × 3 × 7)
= 378
Therefore, the answer is 378.
Answered by
Bot
Sure, we know that:
10P4 = 10! / (10 - 4)!
= 10! / 6!
= (10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1) / (6 × 5 × 4 × 3 × 2 × 1)
= 10 × 9 × 8 × 7
= 5,040
Therefore, the answer is 5,040.
10P4 = 10! / (10 - 4)!
= 10! / 6!
= (10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1) / (6 × 5 × 4 × 3 × 2 × 1)
= 10 × 9 × 8 × 7
= 5,040
Therefore, the answer is 5,040.
Answered by
Bot
Sure, we know that:
8C5 = 8! / (5! × (8 - 5)!)
= 8! / (5! × 3!)
= (8 × 7 × 6 × 5 × 4 × 3 × 2 × 1) / [(5 × 4 × 3 × 2 × 1) × (3 × 2 × 1)]
= 8 × 7 × 2
= 112
Therefore, the answer is 112.
8C5 = 8! / (5! × (8 - 5)!)
= 8! / (5! × 3!)
= (8 × 7 × 6 × 5 × 4 × 3 × 2 × 1) / [(5 × 4 × 3 × 2 × 1) × (3 × 2 × 1)]
= 8 × 7 × 2
= 112
Therefore, the answer is 112.
Answered by
Bot
In mathematics, the exclamation mark (!) symbol is used to denote the factorial of a non-negative integer.
For example, 8! means the product of all positive integers from 1 to 8:
8! = 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 = 40,320.
For example, 8! means the product of all positive integers from 1 to 8:
8! = 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 = 40,320.
Answered by
Bot
You're welcome! Let me know if you have any other questions.
Answered by
Bot
Sure, we know that:
15C3 = 15! / (3! × (15 - 3)!)
= 15! / (3! × 12!)
= (15 × 14 × 13 × 12 × 11 × 10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1) / [(3 × 2 × 1) × (12 × 11 × 10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1)]
= (15 × 14 × 13) / (3 × 2 × 1)
= 455
Therefore, the answer is 455.
15C3 = 15! / (3! × (15 - 3)!)
= 15! / (3! × 12!)
= (15 × 14 × 13 × 12 × 11 × 10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1) / [(3 × 2 × 1) × (12 × 11 × 10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1)]
= (15 × 14 × 13) / (3 × 2 × 1)
= 455
Therefore, the answer is 455.
Answered by
Bot
If you and your 3 friends go to a concert and want to sit in the assigned seats, then there are 4 people in total who need to be seated.
The first person can sit in any of the 4 seats. After the first person chooses a seat, there are only 3 seats left for the second person to choose from. Once the second person chooses a seat, there are only 2 seats left for the third person to choose from. Finally, the last person will have only 1 seat left to choose.
So, the total number of different ways that you and your 3 friends can sit in the assigned seats is:
4 × 3 × 2 × 1 = 24
Therefore, there are 24 different ways that you and your 3 friends can sit in the assigned seats.
The first person can sit in any of the 4 seats. After the first person chooses a seat, there are only 3 seats left for the second person to choose from. Once the second person chooses a seat, there are only 2 seats left for the third person to choose from. Finally, the last person will have only 1 seat left to choose.
So, the total number of different ways that you and your 3 friends can sit in the assigned seats is:
4 × 3 × 2 × 1 = 24
Therefore, there are 24 different ways that you and your 3 friends can sit in the assigned seats.
Answered by
Bot
If you own 6 pairs of jeans and want to take 2 of them with you on vacation, then you need to choose 2 pairs of jeans from the 6 pairs that you own.
The number of ways to choose 2 pairs of jeans from 6 pairs is given by the formula for combinations:
6C2 = 6! / (2! × (6 - 2)!)
= 6! / (2! × 4!)
= (6 × 5 × 4 × 3 × 2 × 1) / [(2 × 1) × (4 × 3 × 2 × 1)]
= 15
Therefore, there are 15 different ways that you can choose 2 pairs of jeans from 6 pairs.
The number of ways to choose 2 pairs of jeans from 6 pairs is given by the formula for combinations:
6C2 = 6! / (2! × (6 - 2)!)
= 6! / (2! × 4!)
= (6 × 5 × 4 × 3 × 2 × 1) / [(2 × 1) × (4 × 3 × 2 × 1)]
= 15
Therefore, there are 15 different ways that you can choose 2 pairs of jeans from 6 pairs.
Answered by
Bot
We know that:
9C4 = 9! / (4! × (9 - 4)!)
= 9! / (4! × 5!)
= (9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1) / [(4 × 3 × 2 × 1) × (5 × 4 × 3 × 2 × 1)]
= (9 × 2 × 3 × 7)
= 378
Therefore, 9C4 is equal to 378.
Note that the second part of your question (the dash) could not be interpreted as it is missing a value or operation after the dash.
9C4 = 9! / (4! × (9 - 4)!)
= 9! / (4! × 5!)
= (9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1) / [(4 × 3 × 2 × 1) × (5 × 4 × 3 × 2 × 1)]
= (9 × 2 × 3 × 7)
= 378
Therefore, 9C4 is equal to 378.
Note that the second part of your question (the dash) could not be interpreted as it is missing a value or operation after the dash.
Answered by
Bot
Sure, I'm here to help! What do you need help with?
Answered by
Bot
The total number of ways that 4 students can be chosen from a class of 12 to represent their class at a banquet is given by the formula for combinations:
12C4 = 12! / (4! × (12 - 4)!)
= 12! / (4! × 8!)
= (12 × 11 × 10 × 9) / (4 × 3 × 2 × 1)
= 495
Therefore, there are 495 different ways that 4 students can be chosen from a class of 12 to represent their class at a banquet.
12C4 = 12! / (4! × (12 - 4)!)
= 12! / (4! × 8!)
= (12 × 11 × 10 × 9) / (4 × 3 × 2 × 1)
= 495
Therefore, there are 495 different ways that 4 students can be chosen from a class of 12 to represent their class at a banquet.
Answered by
Bot
Sure, if there are 6 people (you and 5 friends) who want to sit in the assigned seats at the concert, then the number of ways that they can sit can be calculated using the formula for permutations:
6P6 = 6!
= 6 × 5 × 4 × 3 × 2 × 1
= 720
Therefore, there are 720 different ways that you and 5 friends can sit in the assigned seats at the concert.
6P6 = 6!
= 6 × 5 × 4 × 3 × 2 × 1
= 720
Therefore, there are 720 different ways that you and 5 friends can sit in the assigned seats at the concert.
Answered by
Bot
If you own 5 pairs of jeans and want to take 2 of them with you on vacation, then the number of ways that you can choose 2 pairs to take with you is given by the formula for combinations:
5C2 = 5! / (2! × (5 - 2)!)
= 5! / (2! × 3!)
= (5 × 4 × 3 × 2 × 1) / ((2 × 1) × (3 × 2 × 1))
= 10
Therefore, there are 10 different ways that you can choose 2 pairs of jeans to take with you on vacation.
5C2 = 5! / (2! × (5 - 2)!)
= 5! / (2! × 3!)
= (5 × 4 × 3 × 2 × 1) / ((2 × 1) × (3 × 2 × 1))
= 10
Therefore, there are 10 different ways that you can choose 2 pairs of jeans to take with you on vacation.
Answered by
Bot
You're welcome! Feel free to ask if you have any more questions.