Asked by Ellen B
I am totally stumped... PLEASE if anyone can help we are going nuts...lol
Use the Rieman sum definition of the definite integral to show that
3¡ò(there is a little "b" at top and little "a" at bottom
3¡ò x©÷dx = b©ø-a©ø
Here,for simplicity we assume b>a>0. Specify your mesh/grid Xi, ¥Äx, and your choice of sample points x*/i
my note: i did not know how to put the asterick over the i so i showed it as */i above
and again I WILL LOVE YOU IF SOMEONE CAN HELP ME OMG HELPPPPPPPPPP lol I feel so stupid
Use the Rieman sum definition of the definite integral to show that
3¡ò(there is a little "b" at top and little "a" at bottom
3¡ò x©÷dx = b©ø-a©ø
Here,for simplicity we assume b>a>0. Specify your mesh/grid Xi, ¥Äx, and your choice of sample points x*/i
my note: i did not know how to put the asterick over the i so i showed it as */i above
and again I WILL LOVE YOU IF SOMEONE CAN HELP ME OMG HELPPPPPPPPPP lol I feel so stupid
Answers
Answered by
Steve
I'm stumped by the cryptic symbols. Try the notation
integral[a,b]
x_i or xi for x sub i
Whatever the function, the Riemann sum is evaluated by approximating the actual area with a set of rectangles, whose upper corners are points on the curve.
Review your text, and maybe take a look here:
http://mathworld.wolfram.com/RiemannSum.html
integral[a,b]
x_i or xi for x sub i
Whatever the function, the Riemann sum is evaluated by approximating the actual area with a set of rectangles, whose upper corners are points on the curve.
Review your text, and maybe take a look here:
http://mathworld.wolfram.com/RiemannSum.html
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