Asked by Jendey

On an inclined road, which makes an angle of 25 degrees with the horizontal plane, stands a vertical tower. At a point Q, 150 ft from the base of the tower down the road, the angle of elevation to the top of the tower is 65. How high is the tower?
Answered by Steve
as usual, draw a diagram, and you will see that

(h + 150*sin25°)/(150*cos25°) = tan65°
There are no AI answers yet. The ability to request AI answers is coming soon!