Asked by Sudana
How do i provide ionic equations , for example to this one --> HNO3(aq) + KOH(aq)
Answers
Answered by
DrBob222
Here is how you do ionic equation but I've gone a step further to show how to obtain the net ionic equation which I suspect may be your next question.
Write the full molecular equation and balance it.
HNO3(aq)+ KOH(aq) => KNO3(aq) + H2O(l)
Next step is to write those materials that are ions with this rules.
1. If a gas write it as a molecule with (g)
2. If insoluble write it as a molecule with (s)
3. If a weak electrolyte (such as water or a weak acid or weak base) write as a molecule with (l)
4. Write all others as the ion.
Following those rules,
HNO3 is rule 4.
KOH is rule 4.
KNO3 is rule 4.
H2O is rule 3.
H^+(aq) + NO3^-(aq) + K^+(aq) + OH^-(aq) ==> K^+ +(aq) + NO3^-(aq) + H2O(l)
Step 3 is to cancel those ions common to both sides; i.e., I see NO3^- on both sides and I see K^+ on both sides. Cancel those and you are left with this.
H^+(aq) + OH^-(aq) ==> H2O(l)
This is the net ionic equation.
Write the full molecular equation and balance it.
HNO3(aq)+ KOH(aq) => KNO3(aq) + H2O(l)
Next step is to write those materials that are ions with this rules.
1. If a gas write it as a molecule with (g)
2. If insoluble write it as a molecule with (s)
3. If a weak electrolyte (such as water or a weak acid or weak base) write as a molecule with (l)
4. Write all others as the ion.
Following those rules,
HNO3 is rule 4.
KOH is rule 4.
KNO3 is rule 4.
H2O is rule 3.
H^+(aq) + NO3^-(aq) + K^+(aq) + OH^-(aq) ==> K^+ +(aq) + NO3^-(aq) + H2O(l)
Step 3 is to cancel those ions common to both sides; i.e., I see NO3^- on both sides and I see K^+ on both sides. Cancel those and you are left with this.
H^+(aq) + OH^-(aq) ==> H2O(l)
This is the net ionic equation.
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