Question

Balance the following equation for a half reaction that occurs in basic solution. Use e– as the symbol for an electron.

SO3^2- ---> S2O4^2-

Answer 1

I shall be glad to help you through this but you need to learn to do these yourself. I do these the looong way. The first step is to determine the oxidation step of each element. I will help you here. S on the left is +4 and on the right is +6. Add electrons to the appropriate side to balance the change in oxidation number.
SO3^2- ==> SO4^2- + ?e

Answer 2

Is it:
H2O + SO3^2- ---> SO4^2- +2H^+ + 3e^-

Answer 3

Nevermind I figured it out its:
2SO3^2- + 2H2O + 2e^- ---> S2O4^2- + 4OH^-

Answer 4

NOPE.
You changed SO4^2- on the right to S2O4^2- and you can't do that. Also you have the e on the wrong side. Other than that it is ok.
2OH^- + SO3^2- ==> SO4^2- + 2e + H2O

Answer 5

DrBob222 you're wrong.

Answer 6

2 SO3^-2 + 2 H2O + 2e- -> S2O4^-2 + 4OH-

Answer 7

dr bob is so wrong, good job BOB

Answer 8

Bob forever, all my homies hate Dr Bob.