Asked by keisha
find the value of each of the following when a=2,b=-1 and c=3
1)a(b+c)=2(-1+3)=1
2)4b^2-2ac/a+b+c= 4(-1)^2-2(2)(3)/2+-1+3
ans=-8/4=-2
1)a(b+c)=2(-1+3)=1
2)4b^2-2ac/a+b+c= 4(-1)^2-2(2)(3)/2+-1+3
ans=-8/4=-2
Answers
Answered by
Quidditch
1. You substituted OK, but...
2(-1+3)
=2(2)
=?
2. Again, the substitution is OK, but...
4((-1)^2 - 2(2)(3)/2 + -1 + 3
=4(1) - 12/2 - 1 + 3
=4 - 6 - 1 + 3
=?
2(-1+3)
=2(2)
=?
2. Again, the substitution is OK, but...
4((-1)^2 - 2(2)(3)/2 + -1 + 3
=4(1) - 12/2 - 1 + 3
=4 - 6 - 1 + 3
=?
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