Asked by Anonymous
Automobile batteries use 3.0 M H2SO4 as an electrolyte. How much 1.20 M NaOH will be needed to neutralize 225mL of battery acid?
Answers
Answered by
DrBob222
2NaOH + H2SO4 ==> Na2SO4 + 2H2O
mols H2SO4 = M x L = ?
Using the coefficients in the balanced e4quatioin, convert mols H2SO4 to mols NaOH.
Now M NaOH = mols NaOH/L NaOH. You know mols and M, solve for L NaOH and conert to mL if you wish.
mols H2SO4 = M x L = ?
Using the coefficients in the balanced e4quatioin, convert mols H2SO4 to mols NaOH.
Now M NaOH = mols NaOH/L NaOH. You know mols and M, solve for L NaOH and conert to mL if you wish.
Answered by
Eriny Saad
1.1
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