Asked by Anonymous
use the midpoint rule with the given value of n to approximate the integral. round the answer to four decimal places.
integral 0 to pi/2 2cos^3(x)dx, n=4
M4=????
integral 0 to pi/2 2cos^3(x)dx, n=4
M4=????
Answers
Answered by
Damon
delta x = pi/8
x at pi/16 , 3pi/16, 5pi/16, 7pi/16
so
2 cos^3 pi/16 = 1.887
2 cos^3 3 pi/16 = 1.1497
etc
add them up and multiply by pi/8
x at pi/16 , 3pi/16, 5pi/16, 7pi/16
so
2 cos^3 pi/16 = 1.887
2 cos^3 3 pi/16 = 1.1497
etc
add them up and multiply by pi/8
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.