Asked by Anonymous
                use the midpoint rule with the given value of n to approximate the integral. round the answer to four decimal places. 
integral 0 to pi/2 2cos^3(x)dx, n=4
M4=????
            
        integral 0 to pi/2 2cos^3(x)dx, n=4
M4=????
Answers
                    Answered by
            Damon
            
    delta x = pi/8
x at pi/16 , 3pi/16, 5pi/16, 7pi/16
so
2 cos^3 pi/16 = 1.887
2 cos^3 3 pi/16 = 1.1497
etc
add them up and multiply by pi/8
    
x at pi/16 , 3pi/16, 5pi/16, 7pi/16
so
2 cos^3 pi/16 = 1.887
2 cos^3 3 pi/16 = 1.1497
etc
add them up and multiply by pi/8
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