Question
use the midpoint rule with the given value of n to approximate the integral. round the answer to four decimal places.
integral 0 to pi/2 2cos^3(x)dx, n=4
M4=????
integral 0 to pi/2 2cos^3(x)dx, n=4
M4=????
Answers
Damon
delta x = pi/8
x at pi/16 , 3pi/16, 5pi/16, 7pi/16
so
2 cos^3 pi/16 = 1.887
2 cos^3 3 pi/16 = 1.1497
etc
add them up and multiply by pi/8
x at pi/16 , 3pi/16, 5pi/16, 7pi/16
so
2 cos^3 pi/16 = 1.887
2 cos^3 3 pi/16 = 1.1497
etc
add them up and multiply by pi/8