A steel reinforcing rod is 12 ft. long and 1" thick in diameter. If a cubic foot of steel weighs 490 lb., how much does the rod weigh (to the nearest pound)?

2 answers

V = pi*r^2 * L = pi * (0.5/12)^2 * 12 =
5.45*10^-3 Ft^3. = Vol. of rod.

Wt.=490Lbs/Ft^3 * 5.45*10^-3Ft^3 = 2.67
Lbs.
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