Asked by la fonda
Consider the following equation:
4 NH3(g) + 5 O2(g)= 4 NO(g) + 6 H2O(s)
a) HOw many liters of oxygen are required to react with 205 L NH3? Both gases are STP.
b)How many grams of water vapor can be produced from 25 L NH3 if both gases are STP?
c) How many liters of NO can be produced when 25 L O2 are reacted with 25 L NH3? All gases are at the same temperature and pressure.
I am not understanding how to do this at all. I am stuck completely. Can you please help me.
4 NH3(g) + 5 O2(g)= 4 NO(g) + 6 H2O(s)
a) HOw many liters of oxygen are required to react with 205 L NH3? Both gases are STP.
b)How many grams of water vapor can be produced from 25 L NH3 if both gases are STP?
c) How many liters of NO can be produced when 25 L O2 are reacted with 25 L NH3? All gases are at the same temperature and pressure.
I am not understanding how to do this at all. I am stuck completely. Can you please help me.
Answers
Answered by
DrBob222
When working with gases like this you can take a short cut and use L as if they were mols. Then just use the coefficients to change anything you have to anything you want.
a.
205L NH3 x (5 mols O2/4 mols NH3) = ? L NH3
You try the others.
a.
205L NH3 x (5 mols O2/4 mols NH3) = ? L NH3
You try the others.
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