Asked by Anonymous
A 1500-kg car coast in neutral down a 2.0degrees hill. The car attains a terminal speed of 20.0 m/s. The question is:how much power must the engine deliver to drive the car on a level road at 20.0 m/s?? Help me out please!!
Answers
Answered by
Damon
m g = 1500* 9.81
m g sin theta = 1500 * 9.81 * sin 2 = 514 N propulsive force
Power = force * speed
= 514 N * 20 m/s = 10.27 KW
m g sin theta = 1500 * 9.81 * sin 2 = 514 N propulsive force
Power = force * speed
= 514 N * 20 m/s = 10.27 KW
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