Our nice triangle has hypotenuse length = 10.
As we know, the median from C to AB is 1/2 AB, or 5.
So, we now have triangle AED with legs 5 and 12, so DE = 13.
how to solve ABC is a right triangle with C as the right angle and sides AC=6 cm and BC=8 cm. Line segment CD is drawn perpendicular to both AC and BC at C. If CD=12 cm, find the distance from D to midpoint E of AB.
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