Asked by Amanda
The potential energy of a +2 x 10-6 C charge decreases from 0.15 J to 0.05 J when it is moved from point A to point B. What is the change in electric potential between these two points? Do not enter any (-) sign in your answer.
Answers
Answered by
Damon
Hey, this is the first problem I did for you backwards.
Answered by
Damon
same thing again and again
Volts is potential energy PER UNIT charge
That is why they call Volts electric potential
change in potential energy = charge * volts !!!
Volts is potential energy PER UNIT charge
That is why they call Volts electric potential
change in potential energy = charge * volts !!!
Answered by
Amanda
0.15j-0.05j=0.1
0.1=__*2x10^-6c
0.1/2x10^-6c=___
50000=__
so answer 50000j/c?
0.1=__*2x10^-6c
0.1/2x10^-6c=___
50000=__
so answer 50000j/c?
Answered by
Damon
.1 Joules = 2*10^-6 V
V = .1 * 10^6 /2 = .05*10^6 = 5*10^4
= 50,000 volts
Yes :)
and yes, volts is Joules per coulomb
V = .1 * 10^6 /2 = .05*10^6 = 5*10^4
= 50,000 volts
Yes :)
and yes, volts is Joules per coulomb
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