Question
How much mgs can be obtained from 20g of mg and 20 g of s by the reaction mg+s_>mgs
Answers
DrBob222
A word to the wise. mgs I read as milligrams. The cap key is there for a reason. Use it.
This is a limiting reagent (LR) problem. You know that because amounts are given for BOTH reactants.
Mg + S ==> MgS
Convert 20 g Mg to mols. mol g= grams/molar mass.
Do the same for 20 g S to mols.
Using the coefficients in the balanced equation, convert mols Mg to mols MgS.
Do the same to convert mols S to mols MgS.
It is likely that the two values for MgS will not be the same which means one of them is not right. The correct value in LR problems is ALWAYS the smaller value and the reagent producing that value is the LR.
Using the smaller value, convert mols MgS to g. g = mols x molar mass.
This is a limiting reagent (LR) problem. You know that because amounts are given for BOTH reactants.
Mg + S ==> MgS
Convert 20 g Mg to mols. mol g= grams/molar mass.
Do the same for 20 g S to mols.
Using the coefficients in the balanced equation, convert mols Mg to mols MgS.
Do the same to convert mols S to mols MgS.
It is likely that the two values for MgS will not be the same which means one of them is not right. The correct value in LR problems is ALWAYS the smaller value and the reagent producing that value is the LR.
Using the smaller value, convert mols MgS to g. g = mols x molar mass.