Asked by Anonymous
Identify any real and extraneous solutions for the equations below.
Sqrt p = -1
So, would this have no real or extraneous solutions?
Sqrt p = -1
So, would this have no real or extraneous solutions?
Answers
Answered by
Steve
√p = -1
has no solutions.
√4 = 2, not +2 or -2.
squaring both sides to give
p = 1
gives an extraneous solution, because
√1 = -1
is not true.
√1 = 1
has no solutions.
√4 = 2, not +2 or -2.
squaring both sides to give
p = 1
gives an extraneous solution, because
√1 = -1
is not true.
√1 = 1
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