5000 e^(.03t) = 10000
e^(.03t) = 2
take ln of both sides , and use rules of logs
.03t = ln 2
t = ln 2/.03 = appr 23.1 years
How many years will it take for an initial investment of $5,000 to double if it is invested at a rate of 3% compunded continuously? Compounded annually?
2 answers
if compounded annually
1.03^t = 2
t ln1.03 = ln2
t = ln2/ln1.03 = appr 23.45 years
1.03^t = 2
t ln1.03 = ln2
t = ln2/ln1.03 = appr 23.45 years