Asked by Varaksa
How many ways can seven children sit on a bench? How many of these arrangements are the two oldest always together?
Answers
Answered by
Damon
7! = 5040
if the two oldest are one, then we only really have six
6! = 720
but one could be right and the other left or reverse so twice that many
*2 = 1440
if the two oldest are one, then we only really have six
6! = 720
but one could be right and the other left or reverse so twice that many
*2 = 1440
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