Question
A washing machine spin dryer has a period T. In order to triple the centripetal
acceleration of the clothes in the dryer the period should be ? 3T
A cube of mass 2.0 kg is kept pressed against a vertical wall by applying a horizontal
force of 60N. If the coefficient of friction between the cube and the wall is 0.50, the
frictional force between the cube and the wall is ? 19.6 N
The angle which vector J + (root3)K makes with the y axis is? Pi/3 radians?
Thanks.
acceleration of the clothes in the dryer the period should be ? 3T
A cube of mass 2.0 kg is kept pressed against a vertical wall by applying a horizontal
force of 60N. If the coefficient of friction between the cube and the wall is 0.50, the
frictional force between the cube and the wall is ? 19.6 N
The angle which vector J + (root3)K makes with the y axis is? Pi/3 radians?
Thanks.
Answers
Ac = v^2/R =
c = 2 pi R
Hey, you need to go faster, not slower !
T = c/v = 2 pi R/v
so
v^2 = (2 pi R)^2/T^2
v^2/R = {(2pi)^2/R T^2]
3 v^2/R = {(2pi)^2/R T^2] *3
so 3/T^2 = 1/T'^2
3 T'^2 = T^2
T'^2 = T^2/3
T' = T /sqrt 3
c = 2 pi R
Hey, you need to go faster, not slower !
T = c/v = 2 pi R/v
so
v^2 = (2 pi R)^2/T^2
v^2/R = {(2pi)^2/R T^2]
3 v^2/R = {(2pi)^2/R T^2] *3
so 3/T^2 = 1/T'^2
3 T'^2 = T^2
T'^2 = T^2/3
T' = T /sqrt 3
A cube of mass 2.0 kg is kept pressed against a vertical wall by applying a horizontal
force of 60N. If the coefficient of friction between the cube and the wall is 0.50, the
frictional force between the cube and the wall is ? 19.6 N
----------------------------
If the cube is not accelerating down, the frictional force is equal to the weight (and less than the coef times the normal force)
m g = 2* 9.81 = 19.6 right
force of 60N. If the coefficient of friction between the cube and the wall is 0.50, the
frictional force between the cube and the wall is ? 19.6 N
----------------------------
If the cube is not accelerating down, the frictional force is equal to the weight (and less than the coef times the normal force)
m g = 2* 9.81 = 19.6 right
tan theta = sqrt 3/1
theta = 60 deg = pi/3 right
theta = 60 deg = pi/3 right
Thank you Damon.
You are welcome :)
Thanks Damon
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