Asked by AIRA
Determine the intervals for which the curve r(t)=4sin^3(t)i + 7cos^3(t)j is smooth on [0,2pai]
Answers
Answered by
Anonymous
pi, not pai
dx/dt = 12sin^2(t)cos(t)
dy/dt = -21cos^2(t)sin(t)
dx/dt and dy/dt are both zero when sin(2t)=0, or at multiples of pi/2.
So, the open intervals are (0,pi/2),(pi/2,pi),(pi/3pi/2),(3pi/2,2pi).
The graph bears this out:
enter
parametric plot x=4sin^3(t), y=7cos^3(t)
at wolframalpha dot com
dx/dt = 12sin^2(t)cos(t)
dy/dt = -21cos^2(t)sin(t)
dx/dt and dy/dt are both zero when sin(2t)=0, or at multiples of pi/2.
So, the open intervals are (0,pi/2),(pi/2,pi),(pi/3pi/2),(3pi/2,2pi).
The graph bears this out:
enter
parametric plot x=4sin^3(t), y=7cos^3(t)
at wolframalpha dot com
There are no AI answers yet. The ability to request AI answers is coming soon!