Asked by ronny
if 5/6th of a radioactive sample decay in 70 years and 1/6th remain. how can you find the half life without knowing the decay constant can you help?
Answers
Answered by
drwls
The fraction (1/6) that remains after 70 years satisfies the relation:
1/6 = 2^(-t/T),
where T is the half life and t = 70 years.
Take logs of both sides to solve for T. I'll use logs to base e but it doesn't matter
-1.7918 = -70/T ln 2 = -48.52/T
T = 27.1 years
1/6 = 2^(-t/T),
where T is the half life and t = 70 years.
Take logs of both sides to solve for T. I'll use logs to base e but it doesn't matter
-1.7918 = -70/T ln 2 = -48.52/T
T = 27.1 years
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