Asked by Terri
A lake formed by a newly constructed dam is stocked with 1,000 fish. Their population is expected to increase according to the logistic curve
N=30/(1+29e^-1.35t)
where N is the number of fish, in thousands, expected after t years. The lake will be open to fishing when the number of fish reaches 20,000. How many years, to the nearest year, will this take?
N=30/(1+29e^-1.35t)
where N is the number of fish, in thousands, expected after t years. The lake will be open to fishing when the number of fish reaches 20,000. How many years, to the nearest year, will this take?
Answers
Answered by
Steve
well, just solve for t:
20 = 30/(1+29e^-1.35t)
1+29e^-1.35t = 1.5
e^-1.35t = 0.5/29
-1.35t = -4.060
t = 3
20 = 30/(1+29e^-1.35t)
1+29e^-1.35t = 1.5
e^-1.35t = 0.5/29
-1.35t = -4.060
t = 3
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