Asked by Babak
integral t^2dt from x to x^2
f'(x)=?
f'(x)=?
Answers
Answered by
Steve
well, you can integrate and then take the derivative, and get
f(x) = 1/3 (x^6-x^3)
f'(x) = 2x^5 - x^2
or you can use Leibnitz' Rule and get
(x^2)^2(2x) - (x)^2(1)
= 2x^5 - x^2
read up on it at
http://en.wikipedia.org/wiki/Differentiation_under_the_integral_sign
f(x) = 1/3 (x^6-x^3)
f'(x) = 2x^5 - x^2
or you can use Leibnitz' Rule and get
(x^2)^2(2x) - (x)^2(1)
= 2x^5 - x^2
read up on it at
http://en.wikipedia.org/wiki/Differentiation_under_the_integral_sign
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