Asked by beti
ssume all temperatures to be exact.
A 0.240-kg coffee cup at 27∘C is filled with 0.200kg of brewed coffee at 96∘C. The cup and the coffee come to thermal equilibrium at 84∘C.
Part A
If no heat is lost to the environment, what is the specific heat of the cup material? [Hint: Consider the coffee essentially to be water.]
A 0.240-kg coffee cup at 27∘C is filled with 0.200kg of brewed coffee at 96∘C. The cup and the coffee come to thermal equilibrium at 84∘C.
Part A
If no heat is lost to the environment, what is the specific heat of the cup material? [Hint: Consider the coffee essentially to be water.]
Answers
Answered by
bobpursley
the sum of the heats gained is zero.
Heat gained by cup+heatgained coffee=0
.240ccup*(84-27)+.200*cwater*(84-96)=0
put in the value for thespecifice heat of water (cwater), solve for ccup.
Heat gained by cup+heatgained coffee=0
.240ccup*(84-27)+.200*cwater*(84-96)=0
put in the value for thespecifice heat of water (cwater), solve for ccup.
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