Asked by Anonymous
At a county fair, an adult ticket sold for $6.00, a senior citizen’s ticket for $4.50, and a child’s ticket for $2.00. On Friday, the number of adults and senior citizen’s tickets sold was 5 more than the number of children’s tickets sold. The number of adult tickets sold was 5 more than three times the number of senior citizen’s tickets sold. Total receipts from the ticket sales were $335.00. How many children’s tickets were sold?
:( I don't get how to solve this... I have this:
a+s=5+c
a=5+3(s)
a+s+c=335... but I don't get the numbers... can someone explain?
:( I don't get how to solve this... I have this:
a+s=5+c
a=5+3(s)
a+s+c=335... but I don't get the numbers... can someone explain?
Answers
Answered by
Steve
Not the number of tickets a+s+c = 335, but the value of the tickets.
6.00a + 4.50s + 2.00c = 335.00
Now you have three equations in 3 variables (after clearing fractions:
a - c + s = 5
a - 3s = 5
12a + 4c + 9s = 670
(a,c,s) = (35,40,10)
6.00a + 4.50s + 2.00c = 335.00
Now you have three equations in 3 variables (after clearing fractions:
a - c + s = 5
a - 3s = 5
12a + 4c + 9s = 670
(a,c,s) = (35,40,10)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.