u = x^2+5
du = 2x dx
So, your integral is now
1/2 ∫ du/u
u= lnx
du = 1/x dx
∫sin(u) du
Use u-substitute to compute the following:
A) ∫((x)/((x^2)+5)) dx
B) ∫((sin(ln(x)))/(x)) dx
1 answer
A) ∫((x)/((x^2)+5)) dx
B) ∫((sin(ln(x)))/(x)) dx
1 answer