Question

In a typical electron microscope, the momentum of each electron is about 1.4 10-22 kg-m/s. What is the de Broglie wavelength of the electrons?

Answer 1

Simple. All you need is this equation:

λ = h/p

So, just plug numbers in...

λ = (6.63 x 10^-34 J*s) / (1.4 x 10^-22 kg-m/s)
λ = 4.74 x 10^-12 m

Answer 2

Simple. All you need is this equation:

λ = h/p

So, just plug numbers in...

λ = (6.63 x 10^-34 J*s) / (1.4 x 10^-22 kg-m/s)
λ = 4.74 x 10^-12 m