Asked by Anonymous
In a typical electron microscope, the momentum of each electron is about 1.4 10-22 kg-m/s. What is the de Broglie wavelength of the electrons?
Answers
Answered by
herp_derp
Simple. All you need is this equation:
λ = h/p
So, just plug numbers in...
λ = (6.63 x 10^-34 J*s) / (1.4 x 10^-22 kg-m/s)
λ = 4.74 x 10^-12 m
λ = h/p
So, just plug numbers in...
λ = (6.63 x 10^-34 J*s) / (1.4 x 10^-22 kg-m/s)
λ = 4.74 x 10^-12 m
Answered by
Prabhakar
Simple. All you need is this equation:
λ = h/p
So, just plug numbers in...
λ = (6.63 x 10^-34 J*s) / (1.4 x 10^-22 kg-m/s)
λ = 4.74 x 10^-12 m
λ = h/p
So, just plug numbers in...
λ = (6.63 x 10^-34 J*s) / (1.4 x 10^-22 kg-m/s)
λ = 4.74 x 10^-12 m
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