Asked by Louis
a spherical balloon is filled with water. if the water is leaking out at a rate of 2 cm^3/min, find the rate at which the radius is changing when the volume is v=1000cm^3?
Answers
Answered by
Steve
v = 4/3 pi r^3
when v = 1000, r = ∛(3000/(4pi))
dv/dt = 4 pi r^2 dr/dt
Now just plug in your values for dv/dt and r to get dr/dt.
when v = 1000, r = ∛(3000/(4pi))
dv/dt = 4 pi r^2 dr/dt
Now just plug in your values for dv/dt and r to get dr/dt.
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