in air ,
v = 331.4m/s + 0.606m/s/degree celsius times T
= 331.4 + .606(30)
= 349.58 m/s
time to travel 1.2 km
= 1200/349058 = 3.4327 seconds
in water:
time = 1200/1498 = .801 seconds
time difference = 3.4327 - .801 or 2.63 seconds
for yours, ok, so far, but you have not yet considered the time.
you found the difference in the speeds.
You did not even consider the fact that the distance was 1.2 km.
( I am assuming your formula is correct, and that the temperature does not affect the speed of sound in water. Common sense tells me it should)
I would like to know if my answer is correct. Thanks in advanced!
A person with their head sideways in the water sees a beaver slap its tail on the lake surface 1.2 km away. What is the time difference between the sound heard in the ear listening in the air and the ear hearing the sound transmitted through the water? The speed of sound in water is 1498 m/s and the air temperature is 30 degrees celsius.
For this question I used the speed of air formula and substituted 30 degrees for T (331.4m/s + 0.606m/s/degree celsius times T) and got 349.58 m/s. After that I subtracted 1498 by 349.58 and got 1148.42. Would that be correct?
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