Asked by jerome
find the mean and RMS of v=25sin50πt
over the range t=0 to t=20ms using integration.
i have integrated to: v=-cos(50πt)/2π+c
but i don't know how to get the mean and rms.
over the range t=0 to t=20ms using integration.
i have integrated to: v=-cos(50πt)/2π+c
but i don't know how to get the mean and rms.
Answers
Answered by
Steve
rms = root of the mean of the square.
v = 25 sin 50πt
we want the square:
v^2 = 625 sin^2(50πt)
the mean is ∫[0,20] v^2 dv / 20
= 1/20 ∫[0,20] 625 sin^2(50πt) dt
= 312.5
so, the root mean square is
17.68
the mean is just
1/20 ∫[0,20] 25 sin(50πt) dt = 0
v = 25 sin 50πt
we want the square:
v^2 = 625 sin^2(50πt)
the mean is ∫[0,20] v^2 dv / 20
= 1/20 ∫[0,20] 625 sin^2(50πt) dt
= 312.5
so, the root mean square is
17.68
the mean is just
1/20 ∫[0,20] 25 sin(50πt) dt = 0
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.