Asked by T.J
Limit as x approaches (pi/2)^- of (x-pi/2)*secx
Answers
Answered by
Steve
(x-π/2) secx
since cosx = sin(π/2-x), we have
-(π/2-x)/sin(π/2-x)
that's just like -u/sinu -> -1 as u->0
since cosx = sin(π/2-x), we have
-(π/2-x)/sin(π/2-x)
that's just like -u/sinu -> -1 as u->0
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