Asked by Alexis
If delta H°rxn and delta S°rxn are both positive values, what drives the spontaneous reaction and in what direction at standard conditions?
The spontaneous reaction is
a)enthalpy driven to the left.
b)entropy driven to the right.
c)entropy driven to the left.
d)enthalpy driven to the right.
I can't really picture this in my head because I was thinking if they are both positive then they need to be at high temperature. Then I am stuck. I am confused as what enthalpy and entropy is. I think entropy is delta S then what is enthalpy?
The spontaneous reaction is
a)enthalpy driven to the left.
b)entropy driven to the right.
c)entropy driven to the left.
d)enthalpy driven to the right.
I can't really picture this in my head because I was thinking if they are both positive then they need to be at high temperature. Then I am stuck. I am confused as what enthalpy and entropy is. I think entropy is delta S then what is enthalpy?
Answers
Answered by
DrBob222
I'm not exactly sure I understand the question.
dH is enthalpy. dS is entropy.
dG = dH - TdS
So dG is negative for spontaneity.
I think this is just an algebra exercise but check me out on that.
If dH is + that's the opposite for getting a negative number for dG so that means the reaction is favored to the left but that isn't spontaneous. I think this is driven to the left so A would be correct, in addition to A, BUT that's not a spontaneous direction.
B. If dS is + then -TdS is - and means spontaneous. I think this is the answer.
C. This contradicts A
D. This contradicts B.
If not for that spontaneous statement just before the multiple guesses, I would think it could have two answers. That is, +dH does mean it is driven to the left but that doesn't coincide with the preamble to the answers. Sorry if this confuses you.
dH is enthalpy. dS is entropy.
dG = dH - TdS
So dG is negative for spontaneity.
I think this is just an algebra exercise but check me out on that.
If dH is + that's the opposite for getting a negative number for dG so that means the reaction is favored to the left but that isn't spontaneous. I think this is driven to the left so A would be correct, in addition to A, BUT that's not a spontaneous direction.
B. If dS is + then -TdS is - and means spontaneous. I think this is the answer.
C. This contradicts A
D. This contradicts B.
If not for that spontaneous statement just before the multiple guesses, I would think it could have two answers. That is, +dH does mean it is driven to the left but that doesn't coincide with the preamble to the answers. Sorry if this confuses you.
Answered by
Alexis
Thanks DrBob222!
Answered by
Niger
Dr Bob is wrong, its goes to the right with the driving force of enthalpy
Answered by
CauseWhyNot
Niger is wrong. the correct answer should be entropy driven to the right
Answered by
Anonymous
If Δ𝐻∘rxn and Δ𝑆∘rxn are both positive values, what drives the spontaneous reaction and in what direction at standard conditions?
enthaply-driven to the left
If Δ𝐻∘rxn and Δ𝑆∘rxn are both negative values, what drives the spontaneous reaction and in what direction at standard conditions?
entropy-driven to the left
enthaply-driven to the left
If Δ𝐻∘rxn and Δ𝑆∘rxn are both negative values, what drives the spontaneous reaction and in what direction at standard conditions?
entropy-driven to the left
Answered by
Anonymous
The spontaneous reaction is entropy-driven to the right.
Answered by
Chase
Everyone is wrong. It is enthalpy driven to the left.
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