Asked by Ali
a.) which of the following reactions should have the larger emf under standard conditions & why?
CuSO4 (aq) + Pb (s) goes to PbSO4 (s) + Cu (s);
Cu(NO3)2 (aq) + Pb(s) goes to Pb(NO3)2(aq) + Cu(s)
b.) Calculate delta G for the reaction.
CuSO4 (aq) + Pb (s) goes to PbSO4 (s) + Cu (s);
Cu(NO3)2 (aq) + Pb(s) goes to Pb(NO3)2(aq) + Cu(s)
b.) Calculate delta G for the reaction.
Answers
Answered by
DrBob222
In #1, formation of Pb to Pb^+ should be smaller than Pb ==> PbSO4 because the formation of PbSO4 drives the reaction to the right.
#2. dG = -nFEocell
#2. dG = -nFEocell
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