Your mean is correct
to get a mean of 72, let the extra score be x
and he now has 10 scores to average
(633 + x)/10 = 72
633 + x = 720
x = 720-633 = 87
he needs an 87
or, think of it this way.
to have an average of 72 on 10 tests, he needs a total score of 720
so far he has 633, so he needs 87 more
PS. I did not check your sum of 633, I assume it is correct.
Anxious Billy Bob pulled out his math recording sheet and saw the following scores
54,62,65,68,70,70,78,82,84
A. He want to calculate his average.Which measure of center is the average?compute it ?
I have this :The measure of center is the average, mean
633/9=70.33=about 70%
B.He has one more exam left and he would like to end the marking period with at least a 72 average .What would his last exam score have to be.
?????????
1 answer