Asked by ariel nuevas
Rj and Joshua are running in the fun run. Rj runs at 7kph and Joshua at 5kph. if they start at the same time, how long will it be before Rj is 1/4 km ahead of Joshua?
Answers
Answered by
Steve
since the speed difference is 2 km/hr,
(1/4 km) / (2 km/hr) = 1/8 hr
(1/4 km) / (2 km/hr) = 1/8 hr
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