Asked by Anonymous
What is the de Broglie wavelength of a 5.0-eV electron?
Answers
Answered by
Elena
E=5eV=8•10⁻¹⁹ J
λ=h/p = h/sqrt(2mE) =
=6.63•10⁻³⁴/sqrt(2•9.1•10⁻³¹•8•10⁻¹⁹)=5.5•10⁻¹⁰ m
λ=h/p = h/sqrt(2mE) =
=6.63•10⁻³⁴/sqrt(2•9.1•10⁻³¹•8•10⁻¹⁹)=5.5•10⁻¹⁰ m
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